Re: AttachInterrupt on NodeMCU

2017-03-24T17:53:15+08:00

attachInterrupt expect a pointer to the function, not its returned value. If you call doSth(), you get the returned value, in your case, it's a void.
Try to remove the parenthesis after doSth:

Code:

attachInterrupt(D4, doSth, CHANGE);

Statistics: Posted by Tercero — Fri Mar 24, 2017 5:53 pm

AttachInterrupt on NodeMCU

2017-01-18T22:50:35+08:00

I'm trying to figure out how the AttachedInterrupt works on the NodeMCU.
Everything I found tells me that this code is OK?!

Code:

void setup() {
  Serial.begin(9600);
  pinMode(D4, INPUT);
  attachInterrupt(D4, doSth(), CHANGE);
}

void loop() {
  Serial.println(digitalRead(D4));
  delay(100);
}

void doSth() {
  Serial.println("Check!");
}

But I just get this error:

I still have no idea after hours of research!
Thanks a lot in advance

Statistics: Posted by pxlstuermer — Wed Jan 18, 2017 10:50 pm

ESP8266 Developer Zone

Re: AttachInterrupt on NodeMCU

AttachInterrupt on NodeMCU